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Sample Datasets

Hezaveh uses 192×192192\times192 image size with a pixel size of 0.04" (seconds of arc). This seems to be a reasonable choice to follow.

Proposed Selection Algorithm

This is based on a sketch by Ben David March 2026.

  1. Choose the Einstein radius uniformly at random, so that 0.1"θE3.0"0.1"\le\theta_E\le3.0".

    • where θE=RE/χ\theta_E=R_E/\chi, i.e. RER_E converted to angular units.

  2. Choose the source position inside or around the critical curve, For example, choose the polar coordinates (R,ϕ)(R,\phi)

    • so that RcθER\le c\theta_E for some constant CC, e.g. c=1.2c=1.2.

    • ϕ\phi chosen uniformly at random

  3. Choose the orientation of the elliptical lens uniformly at random.

  4. Choose the orientation of the elliptical source uniformly at random.

  5. CHoose the ellipticity ff of the lens uniformly at random, so that 0.6f0.90.6\le f\le 0.9.

  6. Source parameters - sersic profiel

    • size: 2σ52\le\sigma\le5

    • sersic index 1ns51\le n_s\le 5

    • luminosity 10l2010\le l\le 20, exponentially distributed with λ=2.0\lambda=2.0 (see below)

Proposal from Oda

ParameterHezaveh (arcsec)CosmoSim (512x512)
RER_E0.1"3.0"0.1"\ldots3.0"1391\ldots 39 (resiprocal)
Lens Ellipticity00.90\ldots0.91.00.11.0\ldots 0.1 (resiprocal)
Source Size0.05"0.8"0.05"\ldots0.8"1101\ldots10
Source Position (RR)not specified1101\ldots10
χ\chinot specified50
Lens rotation (θ\theta)not specified0°179°0°\ldots 179°
Source rotation (ϕ\phi)not specified0°359°0°\ldots 359°
Sersisk indeks (n_sersic)N/A151\ldots5
LuminosityN/A102010\ldots20[1]

The exponential distribution used for luminsoty returns u=1expλxu = 1 - \exp{-\lambda\cdot x} where xx is exponentially distributed, that is with a probability density function f(x;λ)=λexpλxf(x;\lambda) = \lambda\exp{-\lambda x} for positive xx.
This uu is scaled to within the given range.

Footnotes
  1. Luminosity is exponentially distributed with λ=2.0\lambda=2.0.