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Critical Curves

Authors
Affiliations
NTNU---Norwegian University of Science and Technology
NTNU---Norwegian University of Science and Technology

We build on the notation defined in Lens Potential. The derivation is based on Congdon & Keeton (2018).

Basic Notation

Working with angular co-ordinates, β\beta denotes the source and θ\theta the image. We consider only a single deflected point.

The amplification tensor AA is given in terms of its inverse which is the Jacobian of the lens mapping.

A(θ)=∂β∂θ=[∂u∂θ1∂u∂θ2∂v∂θ1∂v∂θ2]\mathcal{A}(\boldsymbol{\theta}) = \frac{\partial\boldsymbol{\beta}}{\partial\boldsymbol{\theta}} = \begin{bmatrix} \frac{\partial u}{\partial \theta_1} & \frac{\partial u}{\partial \theta_2} \\ \frac{\partial v}{\partial \theta_1} & \frac{\partial v}{\partial \theta_2} \end{bmatrix}

where β=(u,v)\boldsymbol{\beta}=(u,v) and θ=(θ1,θ2)\boldsymbol{\theta}=(\theta_1,\theta_2).

The raytrace equation is given as

β=θ−∇ψ\boldsymbol{\beta} = \boldsymbol{\theta} - \nabla\psi

which gives

A(θ)=[1−ψθ1θ1−ψθ1θ2−ψθ1θ21−ψθ2θ2]\mathcal{A}(\boldsymbol{\theta}) = \begin{bmatrix} 1 - \psi_{\theta_1\theta_1} & -\psi_{\theta_1\theta_2} \\ -\psi_{\theta_1\theta_2} & 1 - \psi_{\theta_2\theta_2} \end{bmatrix}

We can equivalently write it in normalised screen space co-cordinates

A(x)=[1−ψx1x1−ψx1y2−ψx1y21−ψy2y2]\mathcal{A}(\mathbf{x}) = \begin{bmatrix} 1 - \psi_{x_1x_1} & -\psi_{x_1y_2} \\ -\psi_{x_1y_2} & 1 - \psi_{y_2y_2} \end{bmatrix}

Decomposition

Since A\mathcal{A} is real and symmetric, we can decompose it using the identity matrix and the Pauli spin matrices

R−=[100−1]R/=[0110]R_- = \begin{bmatrix} 1 & 0 \\ 0 & -1 \end{bmatrix} \quad R_/ = \begin{bmatrix} 0 & 1 \\ 1 & 0 \end{bmatrix}

We get

A(x)=(1−κ)I−γ+R−−γ×R/\mathcal{A}(\mathbf{x}) = (1-\kappa)I - \gamma_+R_- - \gamma_\times R_/

where this convergence (or mass distribution) is

κ(θ)=12(ψθ1θ1+ψθ2θ2)\kappa(\theta) = \frac12( \psi_{\theta_1\theta_1} + \psi_{\theta_2\theta_2} )

and

γ+(θ)=12(ψθ1θ1−ψθ2θ2)γ×(θ)=ψθ1θ2\gamma_+(\theta) = \frac12( \psi_{\theta_1\theta_1} - \psi_{\theta_2\theta_2} ) \\ \gamma_\times(\theta) = \psi_{\theta_1\theta_2}

We can then write

A(θ)=[1−κ−γ+−γ×−γ×1−κ+γ+]\mathcal{A}(\boldsymbol{\theta}) = \begin{bmatrix} 1 - \kappa - \gamma_+ & - \gamma_\times \\ - \gamma_\times & 1 - \kappa + \gamma_+ \end{bmatrix}

It is then straight forward to prove that the eigenvalues of A(θ)\mathcal{A}(\boldsymbol{\theta}) are

λ±=(1−κ)±γ+2+γ×2\lambda_\pm = (1 - \kappa) \pm \sqrt{\gamma_+^2 + \gamma_\times^2}

and we can verify that the inverse is given as

A−1(θ)=1(1−κ)2−γ+2−γ×2[1−κ+γ+γ×γ×1−κ−γ+]\mathcal{A}^{-1}(\boldsymbol{\theta}) = \frac1{(1-\kappa)^2 - \gamma_+^2 - \gamma_\times^2} \begin{bmatrix} 1 - \kappa + \gamma_+ & \gamma_\times \\ \gamma_\times & 1 - \kappa - \gamma_+ \end{bmatrix}

Magnification

The magnification of an image is given as

μ(θ)=det⁡A−1(θ)=1det⁡A=λ−λ+=1(1−κ)2−γ+2−γ×2\mu(\boldsymbol{\theta}) = \det \mathcal{A}^{-1}(\boldsymbol{\theta}) = \frac1{\det\mathcal{A}} = \lambda_-\lambda_+ = \frac1{(1-\kappa)^2 - \gamma_+^2 - \gamma_\times^2}

TODO What is the significance of this?

TODO Is this consistent with the inverse magnification given in some sources? The inverse magnification is

μ−1(θ)=βθ⋅dβdθ\mu^{-1}(\theta) = \frac{\beta}{\theta}\cdot\frac{d\beta}{d\theta}

Critical Curves and Caustics

The critical curve is defined as the set of points where the map from source to image plane breaks down, i.e. when the magnification tends to infinity. Thus the critical curve is the solution of the equation det⁡A=0\det\mathcal{A}=0, or

0=λ−λ+=(1−κ)2−γ+2−γ×20 = \lambda_-\lambda_+ = (1-\kappa)^2 - \gamma_+^2 - \gamma_\times^2

TODO Define caustic

References
  1. Congdon, A. B., & Keeton, C. R. (2018). Principles of Gravitational Lensing: Light Deflection as a Probe of Astrophysics and Cosmology. Springer International Publishing. 10.1007/978-3-030-02122-1